Junior WAEC 2025 Questions Mathematics [Revealed!]

This is for BECE Candidates looking for Junior WAEC 2025 Questions and Answers Mathematics. The Mathematics paper is compulsory for all candidates regardless of their school. So, here you will get genuine Junior WAEC 2025 Questions and Answers for Mathematics. Your duty now is to read through them as many times as possible and get ready to smash your forthcoming paper. Remember to use the comments sections if you have questions, and don’t forget to join our Free Online Tutorial Classes on Facebook. (Like and Follow Page)

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What are Junior WAEC 2025 Questions and Answers Mathematics?

Junior WAEC 2025 Questions and Answers Mathematics are the questions you should expect in your Mathematics paper in 2025 BECE, together with their answers.

It is very important that every candidate preparing to sit for Mathematics in the forthcoming 2025 BECE examination should catch a glimpse of these questions.

In so doing, they will know what to expect in the exam hall. Knowing exactly what to expect will boost their confidence and guarantee them a very high score.

Junior WAEC 2025 Mathematics Questions and Answers Revealed!

On this page, we shall reveal Junior WAEC 2025 Questions and Answers for all candidates taking the Mathematics paper.

How lucky you are to stumble upon this important page!

The questions are genuine and the answers are accurate, and all are a product of our burning passion to see you excel in your BECE and proceed to Senior Secondary School.

In the following sections, you will read the Mathematics questions you are to expect in your 2025 Junior WAEC exam as well as their answers. You can use the comments section if you still need clarification over some of the questions. We will give you a more detailed explanation.

BECE is a very serious and important examination. You will answer 60 questions in BECE Mathematics 2025 within 2 hours. So it’s important that you pay attention to the information revealed on this page.

junior waec candidates in bece hall

Junior WAEC 2025 Questions and Answers Mathematics [Numbers 1 – 10]

1. Express 23006 in words
A. Two thousand three hundred and six
B. Twenty three million and six
C. Twenty three billion and six
D. Twenty three thousand and six

2. Approximate 0.002438 to 3 significant figures.
A. 0.0025 B. 0.00244
C. 0.002 D. 0.0024

3. Complete the number pattern of 7, 14, 21, 28,_______
A. 21 B. 28
C. 35 D. 42

4. Express 9 7/10 as an improper fraction
A. 97/100 B. 97/10
C. 19/10 D. 970/10

5. Which number is represented by the Roman numerals CXCIV?
A. 198 B. 197
C. 196 D. 194

6. Convert 11101_two to base ten
A. 29_ten B. 28_ten
D. 26_ten C. 27_ten

7. Express 91/20 as mixed as mixed number
A. 4 12/20 B. 5 11/20
C. 4 11/20 D. 5 12/20

8. Approximate 52,395 to the nearest hundred
A. 52,390 B. 52,400
C. 52,405 D. 53,000

9. What is the L.C.M of 6, 9 and 18.
A. 6 B. 9
C. 12 D. 18

10. Find the value of (x + y)/z, when x = 6, y = 2 and z = 4.
A. 2 B. 3 C. 4 D. 5

Answers to Question Number 1 – 10

1.D 2.D 3.C 4.B 5.D 6.A 7.C 8.B 9.D 10.B

Junior WAEC 2025 Questions and Answers Mathematics [Numbers 11 – 20]

11. Evaluate 6.47 + 340.8 + 73.52 to the nearest whole number.
A. 420 B. 420.7
C. 420.8 D. 421

12. Reduce 48/60 to its lowest terms
A. 4/5 B. 3/5
C. 2/5 D. 4/7

13. Change 5/8 to decimal fractions
A. 0.525 B. 0.635
C. 0.625 D. 0.665

14. Express 85% as a fraction
A. 17/20 B. 13/20
C. 11/20 D. 9/20

15. Convert 17/25 to decimal
A. 0.65 B. 0.66
C. 0.67 D. 0.68

16. Which of these numbers is not divisible by 2?
256, 1056, 390, 511
A. 511 B. 256
C. 1056 D. 390

17. I think of a number, I multiply it by 7. I add 12. The result is 40. What is the number I am thinking of?
A. 4 B. 5 C. 6 D. 7

18. Solve 16 – x = 13
A. 6 B. 5 C. 4 D. 3

19. What is the difference between -3 and 9?
A. 6 B. 7 C. 9 D. 12

20. Express 0.0004381 in standard form.
A. 4.38 x 10⁵
B. 4.381 x 10^-4
C. 4.381 x 10^-4
D. 4.381 x 10⁵

Answers to Question Number 11 – 20

11.D 12.A 13.C 14.A 15.A 16.A 17.B 18.B 19.B 20.B

Junior WAEC 2025 Questions and Answers Mathematics [Numbers 21 – 30]

21. Solve the equation 4 = x/9
A. 38 B. 36 C. 30 D. 24

22. Solve the simultaneous equation.
x + y = 3
x – y = 5
A. x = 6, y = -2
B. x = 4, y = -1
C. x = 3, y = 2
D. x = 2, y = -2

23. Write eight thousand, nine hundred and thirty-four in figure.
A. 8000934 B. 800090034
C. 8934 D. 80934

24. Simplify 2 1/5 ÷ 1/5
A. 2 B. 10 C. 11 D. 13

25. Convert 0.72 to percentage
A. 70% B. 68%
C. 66% D. 72%

26. Simplify 1/2 – 1/3
A. 1/6 B. 1/3
C. 1/4 D. 1/5

27. Find the sum of all odd numbers between 10 and 20.
A. 75 B. 65 C. 55 D. 48

28. The perimeter of a rectangular field is 50m. Find the length of the field if its breadth is 6m
A. 56m B. 44m
C. 24m D. 19m

29. Calculate the value eº in the figure below

A. 100° B. 80°
C. 70° D. 60°

30. Find the area of the triangle below

A. 56cm² B. 50cm²
C. 45cm² D. 25cm²

Answers to Question Number 21 – 30

21.C 22.A 23.C 24.C 25.D 26.A 27.C 28.B 29.C 30.A

Junior WAEC 2025 Questions and Answers Mathematics [Numbers 31 – 40]

31. I add 7 to a certain number. I double the result. My final answer is 34. What was my number?
A. 9 B. 15 C. 4 D. 11

32. Solve 1/5 + 3/10
A. 1/5 B. 1/2
C. 1/3 D. 1/4

33. The sum of angles in a quadrilateral is
A. 180 B. 270
C. 360 D. 90

34. How many sides has a decagon?
A. 5 B. 8 C. 7 D. 10

35. Find the angles of the triangle ABC which has x°, 3x°, and 5x°
A. 80, 40, 60
B. 20, 60, 100
C. 60, 20, 80
D. 40, 80, 60

36. If y is an acute angle, then
A. y < 90° B. y > 90°
C. y < 180° D. 7 > 180°

37. Solve for the unknown b + 3 = 0
A. 3b B. 0 C. 3 D.-3

38. Simplify 1/3 of 39x
A. 9x B. 12x
C. -13x D. 13x

39. Simplify 5a²b³ x 3a⁴b³
A. 15a⁸b⁹B. 15a⁶b⁶
C. 15a²b⁰ D. 15a⁶b⁴

40. If x/12 = 6, then x = ?
A. 71 B. 36 C. 72 D. 24

Answers to Question Number 31 – 40

31.A 32.B 33.C 34.D 35.D 36.A 37.D 38.A 39.A 40.C

Junior WAEC 2025 Questions and Answers Mathematics [Numbers 41 – 50]

41. Solve 7/(3k+1) – 2/k = 0
A. k = 1 B. k = 3
C. k = 2 D. k = 5

42. The shape drawn below is ?

A. An acute-angled triangle
B. An Isosceles triangle
C. A right-angled triangle
D. A quadrilateral

43. Which of the following is NOT a property of parallelogram?
A. The opposite sides are parallel.
B. The opposite sides are equal.
C. The opposite angles are not equal.
D. It has two diagonals.

44. A triangle in which two sides are equal is called_______?
A. Scalene
B. right angle triangle
C. Equilateral
D. Isosceles

45. A quadrilateral has three angles in the order 90°, 100°, 75°. Calculate the fourth angle.
A. 85° B. 95°
C. 100° D. 105°

46. In the figure below, calculate angle y
A. 110° B. 100°
C. 90° D. 80°

47. If tanθ = 3/4, what is the cosine value of the same angle.
A. 3/5 B. 4/5
C. 2/5 D. 1/5

48. Solve the equation 12 + 5a = 22
A. 5 B. 4 C. 3 D. 2

49. What is the H.C.F. of mn² and m²n?
A. m²n² B. mn²
C. mn D. m²n

50. Find the area of a circle whose radius is 7cm (Take π = 22/7).
A. 49cm² B. 154cm²
C. 162cm² D. 169cm²

Answers to Question Number 41 – 50

41.C 42.C 43.C 44.D 45.B 46.B 47.B 48.D 49.C 50.A

Junior WAEC 2025 Questions and Answers Mathematics [Numbers 51 – 60]

51. Find the perimeter of the trapezium ABCD.

A. 11.2km B. 9.2km
C. 7km D. 5.2km

52. In the diagram below, calculate the angle marked y°.

A. 30° B. 45°
C. 65° D. 75°

53. Simplify 8(x – y) – 2(4x – 5y)
A. 18y B. -18y
C. 2x D. 2y

54. Find the mean of the set of numbers 3, 5, 5, 6, 7, 10.
A. 9 B. 6 C. 8 D. 10

55. What is the name given to a chart of information in the form of circle divided into sectors
A. bar chart B. pictogram
C. histogram D. pie chart

56. Calculate the length of the side marked b, correct to 2 significant figures.

A. 4.0cm B. 5.0cm
C. 6.0cm D. 3.0 cm

57. On six working days a garage mended 6, 5, 2, 3 and 2 punctures. Calculate the mean number of punctures per day mended by the garage.
A. 2 B. 3 C. 4 D. 5

58. Write the coordinates of the point marked P.

A. (2, 3) B. (2.0)
C. (3, 0) D. (3, 2)

59. A letter is chosen at random from the word MATHEMATICS. Find the probability that it will be an H.
A. 2/11 B. 4/11
C. 5/11 D. 1/11

60. Calculate the perimeter of a field which measures 80m by 50m
A. 260m B. 280m
C. 300m D. 360m

Answers to Question Number 51 – 60

51.B 52.D 53.B 54.B 55.D 56.B 57.B 58.D 59.D 60.B

SECTION B- ESSAY

Answer all questions in this section.

QUESTION 1
a. A woman spent 1/4 of her salary on drugs and 1/8 on rent, what fraction of her salary is left?
b. Simplify 2 2/3 x 1 1/2 ÷ 4 4/5

QUESTION 2
a. A school has 500 students, 42% are boys. How many girls are in the school?

QUESTION 3
a. What is the H.C.F. of 4x³y² and 36x²y⁸
b. Solve the equation (2x + 7)/2 + (x – 5)/3 = 0

QUESTION 4
a. The average mark of the best six girls in a class is 70%. If the average of best fine girls is 72%, calculate the mark of the 6th girl.
b. Simplify (y + x)² – 2xy

Answers to Section B (Essay) Questions of Junior WAEC 2025 Mathematics

QUESTION 1

a. A woman spent 1/4 of her salary on drugs and 1/8 on rent. What fraction of her salary is left?

To find the fraction of the salary left, we first add the fractions spent on drugs and rent.

$spent=14+18\text{Total spent} = \frac{1}{4} + \frac{1}{8}$

To add these, we need a common denominator. The least common denominator of 4 and 8 is 8.

$14=28\frac{1}{4} = \frac{2}{8}$

So,

$14+18=28+18=38\frac{1}{4} + \frac{1}{8} = \frac{2}{8} + \frac{1}{8} = \frac{3}{8}$

Now, subtract this from the total salary (which is 1 or $88\frac{8}{8}$ ):

$left=1−38=88−38=58\text{Fraction left} = 1 – \frac{3}{8} = \frac{8}{8} – \frac{3}{8} = \frac{5}{8}$

Answer: The fraction of the salary left is $58\frac{5}{8}$ .

b. Simplify $\frac{2}{3} \times 1 \frac{1}{2} \div 4 \frac{4}{5}$

First, convert all mixed numbers to improper fractions:

$\frac{2}{3} = \frac{8}{3}, \quad 1 \frac{1}{2} = \frac{3}{2}, \quad 4 \frac{4}{5} = \frac{24}{5}$

Now, the expression becomes:

$83×32÷245\frac{8}{3} \times \frac{3}{2} \div \frac{24}{5}$

To divide by a fraction, multiply by its reciprocal:

$83×32×524\frac{8}{3} \times \frac{3}{2} \times \frac{5}{24}$

Now, multiply the numerators and denominators:

$8×3×53×2×24=120144\frac{8 \times 3 \times 5}{3 \times 2 \times 24} = \frac{120}{144}$

Simplify the fraction by dividing both the numerator and denominator by their GCD, which is 24:

$120÷24144÷24=56\frac{120 \div 24}{144 \div 24} = \frac{5}{6}$

Answer: The simplified result is $56\frac{5}{6}$ .

QUESTION 2

a. A school has 500 students, 42% are boys. How many girls are in the school?

First, find the number of boys:

$boys=42100×500=210\text{Number of boys} = \frac{42}{100} \times 500 = 210$

The total number of students is 500, so the number of girls is:

$girls=500−210=290\text{Number of girls} = 500 – 210 = 290$

Answer: There are 290 girls in the school.

QUESTION 3

a. What is the H.C.F. of $4x^3y^2$ and $36x^2y^8$ ?

To find the H.C.F. (highest common factor), look at the coefficients and the powers of the variables.

The coefficients are 4 and 36. The H.C.F. of 4 and 36 is 4.
The lowest power of is $x^2$ , since the powers are $x^3$ and $x^2$ .
The lowest power of is $y^2$ , since the powers are $y^2$ and $y^8$ .

Thus, the H.C.F. is:

$H.C.F.=4x2y2\text{H.C.F.} = 4x^2y^2$

Answer: The H.C.F. is $4x^2y^2$ .

b. Solve the equation

First, find a common denominator for the fractions. The least common denominator (LCD) of 2 and 3 is 6. Multiply the whole equation by 6 to eliminate the denominators:

$\times \left( \frac{2x + 7}{2} \right) + 6 \times \left( \frac{x – 5}{3} \right) = 6 \times 0$

This simplifies to:

Now, expand both sides:

Combine like terms:

Now, solve for $x$ :

$\quad \Rightarrow \quad x = \frac{-11}{8}$

Answer: $\frac{-11}{8}$ .

QUESTION 4

a. The average mark of the best six girls in a class is 70%. If the average of the best five girls is 72%, calculate the mark of the 6th girl.

Let the total mark of the best six girls be $T_6$ , and the total mark of the best five girls be $T_5$ .

Since the average of the best six girls is 70%, we have:

$T6=6×70=420T_6 = 6 \times 70 = 420$

The average of the best five girls is 72%, so:

$T5=5×72=360T_5 = 5 \times 72 = 360$

The mark of the 6th girl is:

$girl=T6−T5=420−360=60\text{Mark of the 6th girl} = T_6 – T_5 = 420 – 360 = 60$

Answer: The mark of the 6th girl is 60%.

b. Simplify $y + x)^2 – 2xy$

First, expand :

$y + x)^2 = y^2 + 2xy + x^2$

Now, subtract :

$y^2 + 2xy + x^2) – 2xy = y^2 + x^2$

Answer: The simplified expression is $y^2 + x^2$ .

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